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2008第四届泛珠三角洲物理竞赛力学基础试题答案


! !

(4

×10 = 40 1 B 2 D
-!

) 3 E 4 A )! 5 F 6 C 7 C 8 D 9 A 10 B

11. (14 (1)! v1 = (2) l = 3 12. (15

5Gm R , T1 = 4πR < !! 4R 5Gm 12 R /! 5
, )

(1) ?= 0.25; (2) s= 16.25m; (3) t≈ 2.85s.

13. (15

,

)

(1) k =3; (2) ?

gR , 2

gR 9 , mg ; (3) ? 2gR , 0 ; 2 2

(4) n=1,3, 5, …- ?

gR , 2

gR ; n=2,4,6, …-! ? 2gR , 0 . 2
)

14. (15

-!

(1) L = πklθ ; (2) v0 = gl (k 2θ 2 +
(

π2
4

+

1

π2

? 1) , tan α =

π2 ?2 . 2πkθ

; sin θ = θ , 2(1 ? cosθ ) = θ !at θ <50.)

15. (21 (1a)
(1b)

,

)

T = 2π (1c)

L ρ1 + ρ 2 ? g ρ 2 ? ρ1 ; 2π ( ρ1 + ρ 2 ) L . ) 6 ( ρ 2 ? ρ1 ) g

(2) s=2.5L, t = ( 6 +


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